Who Put The Hole In The Swiss Cheese ?

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Add the letters P – U – T to complete the following words and phrases :

 

out __ __ __

 

in __ __ __

 

__ __ s __ ule

 

__ __ __ out

 

__ __ __ on

 

__ __ __ over

 

__ __ __ through

 

__ __ __ refy

 

__ __ __ amen

 

__ __ __ ativer

 

__ __ __ chock

 

__ __ __ log

 

__ __ rsui __

 

dis __ __ __ e

 

Ras __ __ __ in

 

__ __ rsui __

 

__ __ __ ting

 

__ __ __ by

 

__ __ __ back

 

__ __ __ forward

 

__ __ __ across

 

__ __ __ to

 

__ __ __ in

 

__ yrol __ si __ e

 

__ __ rpor __

 

__ __ ri __ anical

 

__ __ ri __ y

 

__ __ ppe __

 

__ __ n __

 

__ __ ndi __

 

__ __ ngen __

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When Jack went for a picnic beneath the beanstalk, he found that there were a number of different sized holes in the Swiss cheese. Using the mathematical formula for calculating the area of a circle – pie x radius x radius (3.14 r 2), fill in the missing gaps in the table. Which animal has been eating which part of the cheese ? Who had made which hole in the Swiss cheese ? Work out your answer by using the mathematical formula above and show your working out

Animal     Diameter / Body Width

1. Worm    4 cm

2. Snail      5 cm

3. Snake    8 cm

4. Slug      2.5 cm

5. Caterpillar 3 cm

Area of the hole

7.065 sq cm

12.56 sq cm

4.906 sq cm

19.625 sq cm

50.24 sq cm

© Jacqueline Richards 2007

Answers :

outputinput

pustule

put out

put on

put over

put through

putrefy

putamen

putativer

putchock

putlog

pursuit

dispute

Rasputin

pursuitputting

put by

put back

put forward

put across

put to

put in

pyrolusite

purport

puritanical

purity

puppet

punt

pundit

pungent

Answers :

Animal Diameter Formula Area of the hole

1. Worm 4 cm 3.14 x 2 x 2 = 12.56 sq cm

2. Snail 5 cm 3.14 (2.5 x 2.5) = 19.625 sq cm

3. Snake 8 cm 3.14 x 4 x 4 = 50.24 sq cm

4. Slug 2.5 cm 3.14 (1.25 x 1.25) = 4.906 sq cm

5. Caterpillar 3 cm 3.15 x 1.5 x 1.5 = 7.065 sq cm

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