Add the letters P – U – T to complete the following words and phrases :

out __ __ __

in __ __ __

__ __ s __ ule

__ __ __ out

__ __ __ on

__ __ __ over

__ __ __ through

__ __ __ refy

__ __ __ amen

__ __ __ ativer

__ __ __ chock

__ __ __ log

__ __ rsui __

dis __ __ __ e

Ras __ __ __ in

__ __ rsui __

__ __ __ ting

__ __ __ by

__ __ __ back

__ __ __ forward

__ __ __ across

__ __ __ to

__ __ __ in

__ yrol __ si __ e

__ __ rpor __

__ __ ri __ anical

__ __ ri __ y

__ __ ppe __

__ __ n __

__ __ ndi __

__ __ ngen __

When Jack went for a picnic beneath the beanstalk, he found that there were a number of different sized holes in the Swiss cheese. Using the mathematical formula for calculating the area of a circle – pie x radius x radius (3.14 r 2), fill in the missing gaps in the table. Which animal has been eating which part of the cheese ? Who had made which hole in the Swiss cheese ? Work out your answer by using the mathematical formula above and show your working out

**Animal Diameter / Body Width**

1. Worm 4 cm

2. Snail 5 cm

3. Snake 8 cm

4. Slug 2.5 cm

5. Caterpillar 3 cm

**Area of the hole**

7.065 sq cm

12.56 sq cm

4.906 sq cm

19.625 sq cm

50.24 sq cm

© Jacqueline Richards 2007

Answers :

outputinput

pustule

put out

put on

put over

put through

putrefy

putamen

putativer

putchock

putlog

pursuit

dispute

Rasputin

pursuitputting

put by

put back

put forward

put across

put to

put in

pyrolusite

purport

puritanical

purity

puppet

punt

pundit

pungent

Answers :

Animal Diameter Formula Area of the hole

1. Worm 4 cm 3.14 x 2 x 2 = 12.56 sq cm

2. Snail 5 cm 3.14 (2.5 x 2.5) = 19.625 sq cm

3. Snake 8 cm 3.14 x 4 x 4 = 50.24 sq cm

4. Slug 2.5 cm 3.14 (1.25 x 1.25) = 4.906 sq cm

5. Caterpillar 3 cm 3.15 x 1.5 x 1.5 = 7.065 sq cm